Published by:
CGP EDU Academic Team
Published on: August 12, 2026
Section 2 (Maximum Marks: 32)
This section contains EIGHT questions.
Each question has FOUR options
A
, x = n, y = n, K Sr = 129MeV, K Xe = 86 MeV
B
, x = p, y = e - , K Sr = 129 MeV, K Xe = 86 MeV
C
and x = p, y = n, K Sr = 129 MeV, K Xe = 86 MeV
D
. ONE OR MORE THAN ONE of these four option(s) is(are) correct. Marking scheme: +4 If only the bubble(s) corresponding to all the correct option(s) is(are) darkened. 0 If none of the bubbles is darkened -2 In all other cases A fission reaction is given by 
, where x and y are two particles. Considering 
to be at rest, the kinetic energies of the products are denoted by K Xe , K Sr , K x (2MeV) and K y (2MeV), respectively. Let the binding energies per nucleon of 
and 
be 7.5 MeV, 8.5 MeV and 8.5 MeV respectively. Considering different conservation laws, the correct option(s) is(are) x = n, y = n, K Sr = 86 MeV, K Xe = 129 MeV
, where x and y are two particles. Considering to be at rest, the kinetic energies of the products are denoted by K Xe , K Sr , K x (2MeV) and K y (2MeV), respectively. Let the binding energies per nucleon of and be 7.5 MeV, 8.5 MeV and 8.5 MeV respectively. Considering different conservation laws, the correct option(s) is(are) x = n, y = n, K Sr = 86 MeV, K Xe = 129 MeV
Text Solution
Verified by ExpertsThe correct answer is:
A
Q value of reaction = (140 + 94) × 8.5 – 236 × 7.5 = 219 Mev
So, total kinetic energy of Xe and Sr = 219 – 2 – 2 = 215 Mev
So, by conservation of momentum, energy, mass and charge, only option is correct
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